PHP表单验证内容是否为空的实现代码
(编辑：jimmy 日期: 2026/1/13 浏览：2)
内容为空效果图为：
填写内容效果图：
下面是验证程序的代码：
<!doctype html>
<html>
<head>
<meta http-equiv="conent-type" content="text/html" charset="utf-8"/>
<style>
.red{
color:red;
}
</style>
</head>
<body>
<"";
$nameerr=$emailerr=$weberr=$commenterr=$gendererr="";
if($_SERVER['REQUEST_METHOD']=="POST"){
if(empty($_POST['name'])){
$nameerr="必填名字";
}else{
$name=test_input($_POST['name']);
}
if(empty($_POST['email'])){
$emailerr="必填邮件";
}else{
$email=test_input($_POST['email']);
}
if(empty($_POST['web'])){
$weberr="必填网址";
}else{
$web=test_input($_POST['web']);
}
if(empty($_POST['comment'])){
$commenterr="必填备注";
}else{
$comment=test_input($_POST['comment']);
}
if(empty($_POST['gender'])){
$gendererr="必填备注";
}else{
$gender=test_input($_POST['gender']);
}
}
"red">*必填字段</span>
<form method="POST" action="<">
名字：<input type="text" name="name"/><span class="red"><"*".$nameerr;"text" name="email"/><span class="red"><"*".$emailerr;"text" name="web"/><span class="red"><"*".$weberr;"10" cols="40" name="comment"></textarea><span class="red"><"*".$commenterr;"radio" name="gender" value="男"/>男<input type="radio" name="gender" value="女"/>女<span class="red"><"*".$gendererr;"submit" value="提交验证"/>
</form>
<"名字".$name;
echo "<br/>";
echo "E-mail：".$email;
echo "<br/>";
echo "网址：".$web;
echo "<br/>";
echo "备注：".$comment;
echo "<br/>";
echo "性别：".$gender;
echo "<br/>";
?>
</body>
</html>
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